Two vectors are given by a = 1.8 x - 9.6 y and b = -17.5 x + 1.6 y. What is the magnitude of a?
What is the angle between vector b and the positive x-axis?
What is the magnitude of the vector a + b?
The magnitude of a vector
V=pi+qj
is √(p²+q²).
The angle is given by
arcTan2(q/p) from the i axis if p≠0, or 90 or 270° if p=0 and q>0 or q<0.
sorry but i still don't understand can elaborate on your answer.
consider any vector f= Ax + By
where x,y are coordinates, 90 degrees separated.
The magnitude of f is given by sqrt(A^2+B^2)
so do that above.
thanks for the help
i got the answers for a&c but i cant get b
can you explain further
b = -17.5 x + 1.6 y
the end point of the vector is in the second quadrant (x<0, y>0)
y=1.6
x=-17.5
angle with the x-axis is
tan-11.6/-17.5=(180-5.2)° (second quadrant)
thanks
i did 360-5.2 instead
360-5.2 would lie in the fourth quadrant, and applies when x=17.5 and y=-1.6, which is not the present case.
i tried 180-5.2=174.8
but it was incorrect
Was 354.8 correct?
Did you check the number of decimals requested?
Is it supposed to be in degrees or radians?