an automobile with an initial speed of 4.30 m/s accelerates uniformly at the rate of 3.00m/s^2. fine the final speed and the displacement after 5.00s
Vf=19.3 m/s
Change in Displacement = 59 meters
For the final speed (don't know displacement)
v=4.3+(3x5)
v=4.3+15
v=19.3 m/s^2
Well, well, well, we have an automobile in need of some speed and distance calculations! Let's put on our racing helmets and get to work, shall we?
To find the final speed of our automobile, we can use the glorious formula: final speed = initial speed + (acceleration × time). Plugging in the values we have, we get:
Final speed = 4.30 m/s + (3.00 m/s^2 × 5.00 s)
Now, let's do some math magic:
Final speed = 4.30 m/s + (15.00 m/s)
And voila! Our final speed is:
Final speed = 19.30 m/s
Now, how about that displacement, huh? To find the displacement, we can use another delightful formula: displacement = (initial speed × time) + (0.5 × acceleration × time^2). Let's work it out:
Displacement = (4.30 m/s × 5.00 s) + (0.5 × 3.00 m/s^2 × (5.00 s)^2)
Now, let's put our numerical skills to the test:
Displacement = 21.50 m + (0.5 × 3.00 m/s^2 × 25.00 s^2)
Displacement = 21.50 m + 37.50 m
Drumroll, please! The displacement after 5.00 seconds is:
Displacement = 59.00 m
There you have it, my friend! The final speed is 19.30 m/s, and the displacement is 59.00 m. Ready to hit the road?
To find the final speed of the automobile, you can use the formula:
Final speed (v) = Initial speed (u) + (Acceleration (a) × Time (t))
In this case, the initial speed (u) is 4.30 m/s, the acceleration (a) is 3.00 m/s^2, and the time (t) is 5.00s.
Plugging in the values into the formula:
v = 4.30 m/s + (3.00 m/s^2 × 5.00s)
v = 4.30 m/s + 15.00 m/s
v = 19.30 m/s
Therefore, the final speed of the automobile after 5.00s is 19.30 m/s.
To find the displacement of the automobile after 5.00s, you can use the formula:
Displacement (s) = Initial speed (u) × Time (t) + 0.5 × Acceleration (a) × Time (t)^2
In this case, the initial speed (u) is 4.30 m/s, the acceleration (a) is 3.00 m/s^2, and the time (t) is 5.00s.
Plugging in the values into the formula:
s = (4.30 m/s × 5.00s) + (0.5 × 3.00 m/s^2 × (5.00s)^2)
s = 21.50 m + (0.5 × 3.00 m/s^2 × 25.00s^2)
s = 21.50 m + 0.5 × 3.00 m/s^2 × 625.00s^2
s = 21.50 m + 0.5 × 1875.00 m/s^2s^2
s = 21.50 m + 937.50 m
s = 959.00 m
Therefore, the displacement of the automobile after 5.00s is 959.00 m.