What weight of copper(II) oxide, CuO, would theoretically be produced from 1.623 grams of copper? (mol. masses Cu = 63.55; O = 16.00)
Mass of CuO / Mass of Cu = (63.55+16)/63.55 = 1.252
So from 1.623 g of Cu, you'd get...
So from 1.623 g of Cu, I'd get:
ANS: 1.252 X 1.623 g of Cu = 2.032 g OR
ANS: 1.623 g of Cu/1.252 = 1.296 g? OR
ANS: 1.623 - 1.252 = 0.371 g
I am still confused what you mean by that question.
To answer this question, we need to calculate the molar mass of copper(II) oxide, CuO, and then use stoichiometry to convert the given mass of copper to the theoretical mass of copper(II) oxide.
1. Calculate the molar mass of CuO:
- The molar mass of copper (Cu) is 63.55 g/mol.
- The molar mass of oxygen (O) is 16.00 g/mol.
- Since CuO has one copper atom and one oxygen atom, the molar mass of CuO is the sum of the molar masses of Cu and O:
Molar mass of CuO = Atomic mass of Cu + Atomic mass of O
= 63.55 g/mol + 16.00 g/mol
= 79.55 g/mol
2. Use stoichiometry to convert grams of copper (Cu) to grams of copper(II) oxide (CuO):
- The balanced chemical equation for the reaction between copper and copper(II) oxide is:
2 Cu + O2 -> 2 CuO
- According to the stoichiometry of the reaction, 2 moles of Cu react to form 2 moles of CuO.
- Therefore, the molar ratio between Cu and CuO is 2:2, or 1:1.
- This means that for every 1 mole of Cu, we get 1 mole of CuO.
- We can use this molar ratio to convert the mass of Cu to the mass of CuO:
- First, calculate the number of moles of Cu using its molar mass:
Moles of Cu = Mass of Cu / Molar mass of Cu
= 1.623 g / 63.55 g/mol (molar mass of Cu)
≈ 0.0255 mol (rounded to four decimal places)
- Since the molar ratio between Cu and CuO is 1:1, the moles of CuO will be the same as moles of Cu.
- The mass of CuO can be calculated using its molar mass:
Mass of CuO = Moles of CuO * Molar mass of CuO
= 0.0255 mol * 79.55 g/mol (molar mass of CuO)
≈ 2.03 g (rounded to two decimal places)
Therefore, theoretically, the weight of copper(II) oxide (CuO) produced from 1.623 grams of copper would be approximately 2.03 grams.