I need to division which is (x^2-6x-27)/(x+3)

when I do it I get an answer of (x-9)-27/x+3 but it seems to be wrong. Can someone see what mistake I did... THANKS

you have to do long division

i got x-9 as the answer

thank you....you were right

To divide the polynomial (x^2 - 6x - 27) by (x + 3), you can use polynomial long division. Here are the steps:

1. Arrange the dividend (x^2 - 6x - 27) and divisor (x + 3) in long division format:
```
x - 9
_______________
x + 3 | x^2 - 6x - 27
```

2. Divide the leading term of the dividend (x^2) by the leading term of the divisor (x). The result is x.
```
x - 9
_______________
x + 3 | x^2 - 6x - 27
- x^2 + 3x
__________
-9x - 27
```

3. Multiply the divisor (x + 3) by the result from step 2 (x) and subtract it from the dividend, line by line.
```
x - 9
_______________
x + 3 | x^2 - 6x - 27
- x^2 + 3x
__________
-9x - 27
-(-9x - 27)
______________
0
```

Since the remainder is 0, we can conclude that the division is exact. The quotient is x - 9.

Therefore, the correct answer is (x - 9) with no remainder.