What mass of protons would be required to just neutralize the charge of 1.5 g of electrons?
my teacher said .0015kg times 1e-/.00091e-27kg times 1pt/1e- times 1.67262e-27 over 1 p
chem - bobpursley, Tuesday, September 21, 2010 at 6:48pm
That is what I would do also. But I think you ought to know why that is the method.
figure number electrons in 1.5g:
number electrons: .0015kg/9.11E-31
now figure the mass of the same number of protons:
1.67E-27kg*(.0015/9.11E-31)
chem - Sara, Tuesday, September 21, 2010 at 6:50pm
do i add the e-27 and e-31. i forget
chem - bobpursley, Tuesday, September 21, 2010 at 6:56pm
a^b/a^c= a^(b-c)
chem - Sara, Tuesday, September 21, 2010 at 6:59pm
what? sry im not getting this...
chem - Sara, Tuesday, September 21, 2010 at 8:30pm
so i got 8.087535951e20 kg. my anser is suppose to be in grams so would it be 8087.535951e17?
does this sound right/what u got?
thanks
1.67E-27kg*(.0015/9.11E-31) =2.75
so three protons.
To determine the mass of protons required to neutralize the charge of 1.5 g of electrons, you can follow these steps:
1. First, find the number of electrons in 1.5 g of electrons. Divide the mass of electrons (1.5 g) by the mass of a single electron (9.11 x 10^-31 kg) to get the number of electrons:
Number of electrons = 1.5 g / 9.11 x 10^-31 kg
2. Now, you need to find the mass of the same number of protons. Use the mass of a single proton (1.67262 x 10^-27 kg) and multiply it by the ratio of the number of electrons to the mass of a single electron:
Mass of protons = (1.67262 x 10^-27 kg) * (Number of electrons / mass of a single electron)
To simplify this calculation, you can rewrite the expression using the exponent rules:
Mass of protons = (1.67262 x 10^-27 kg) * (Number of electrons / 9.11 x 10^-31 kg)
Now, substitute the value of the number of electrons from step 1 into the equation.
After performing the calculation, you should get the answer in kilograms. To convert it to grams, multiply by 1000 since there are 1000 grams in 1 kilogram.
Therefore, the answer should be 8087.535951 x 10^17 grams.