An airplane has a mass of 34,500 kg and takes off under the influence of a constant net force of 44,500 N. What is the net force that acts on the plane's 79 kg pilot?
To find the net force acting on the pilot, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration. Mathematically, it can be expressed as:
Fnet = m * a
In this case, we are given the mass of the airplane (34,500 kg) and the net force acting on it (44,500 N). However, we need to find the net force acting on the pilot, not the airplane.
To calculate the net force acting on the pilot, we can assume that the pilot and the airplane are experiencing the same acceleration since they are physically connected during takeoff. Therefore, the net force acting on the pilot can be determined by using the mass of the pilot.
Given that the mass of the pilot is 79 kg, we can substitute this value into the equation:
Fnet = m * a
44,500 N = 79 kg * a
To find the acceleration a, we divide both sides of the equation by the mass m:
a = 44,500 N / 79 kg
Now we can calculate the acceleration:
a = 564.56 m/s^2
Finally, we substitute the acceleration back into the equation to find the net force acting on the pilot:
Fnet = m * a
Fnet = 79 kg * 564.56 m/s^2
Fnet ≈ 44,596.24 N
Therefore, the net force that acts on the pilot is approximately 44,596.24 Newtons.
F=Ma
M =79kg
a= 9.8ms^-2 (gravity)
There is no other acceleration component since the aeroplane is at constant velocity
so
Force on pilot is...
79 x 9.8 = 774.2 N