An unknown substance has a mass of 17.3 . When the substance absorbs 1.557×102 of heat, the temperature of the substance is raised from 25.0 to 45.0 . What is the most likely identity of the substance?

q = m x Cg x (Tf - Ti)

http://www.ausetute.com.au/heatcapa.html

find Cg.

17.3 WHAT?

25 WHAT? 45 WHAT?

To determine the identity of the substance, we can use the equation q = mcΔT, where q represents the amount of heat absorbed, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

First, let's calculate the change in temperature:

ΔT = final temperature - initial temperature
ΔT = 45.0 °C - 25.0 °C
ΔT = 20.0 °C

Next, let's rearrange the formula to solve for specific heat capacity (c):

c = q / (m * ΔT)

Now we can substitute the given values into the equation:

c = (1.557×102 J) / (17.3 g * 20.0 °C)
c = 1557 J / 346 g°C

To simplify the unit, we divide both the numerator and denominator by 346:

c ≈ 4.50 J/g°C

By comparing this specific heat capacity value to known substances, we can determine the most likely identity of the substance.