The Specific Gravity of kerosene is 0.786/ What is the volume occupied by 7.75kg of kerosene?
mass/volume=density
volume=mass/density.
but specific gravity and density are the same when compared to water, so
volume=7.75kg/(1kg/liter)=7.75 liters.
so it's 7.75/0.786?
To find the volume occupied by 7.75 kg of kerosene, we can use the formula:
Volume = Mass / Specific Gravity
First, let's calculate the volume using the given information:
Mass of kerosene = 7.75 kg
Specific Gravity of kerosene = 0.786
Volume = 7.75 kg / 0.786
Now, divide the mass by the specific gravity to find the volume:
Volume = 9.853 kg
So, the volume occupied by 7.75 kg of kerosene is approximately 9.853 liters (L).
To find the volume occupied by 7.75 kg of kerosene, we need to use the formula:
Volume = Mass / Specific Gravity
Given that the Specific Gravity of kerosene is 0.786 and the mass is 7.75 kg, we can substitute the values into the formula to find the volume. Let's calculate it:
Volume = 7.75 kg / 0.786
To get the answer, divide the mass by the Specific Gravity:
Volume = 9.86 liters
Therefore, the volume occupied by 7.75 kg of kerosene is 9.86 liters.