a. When a ball is thrown straight up, by how much does the speed decrease each second?
b. After the ball reaches the top and begins its return back down, by how much does its speed increase each second?
c. Compare the times going up and coming down.
Please Help!!
Thanks!! :)
10m/s i believe and that is going up and down if you neglect air resistance
10m/s for which question (a. b. or c.)?
And also how did you get that answer?
Thanks!
a. When a ball is thrown straight up, its speed decreases by approximately 9.8 m/s^2 (meters per second squared) each second. This is due to the acceleration due to gravity, which acts in the opposite direction of the ball's motion and causes it to slow down.
To calculate the decrease in speed each second, you can use the equation for acceleration: a = Δv/Δt, where a is the acceleration, Δv is the change in velocity, and Δt is the time interval. In this case, the acceleration is -9.8 m/s^2, and the time interval is 1 second. Rearranging the equation, we have: Δv = a * Δt. Plugging in the values, Δv = -9.8 m/s^2 * 1 s = -9.8 m/s.
Therefore, the speed of the ball decreases by 9.8 m/s each second when thrown straight up.
b. After the ball reaches the top and begins its return back down, its speed increases by approximately 9.8 m/s^2 each second. This is because the acceleration due to gravity acts in the same direction as the ball's motion, causing it to speed up as it falls down.
Using the same equation, a = Δv/Δt, but with a positive value for acceleration (+9.8 m/s^2), we can calculate the increase in speed each second. Plugging in the values, Δv = 9.8 m/s^2 * 1 s = 9.8 m/s.
Therefore, the speed of the ball increases by 9.8 m/s each second when it starts falling back down.
c. The time it takes for the ball to go up and come back down is not equal. This is because the ball's speed is constantly changing due to the force of gravity.
When the ball is thrown straight up, it reaches its maximum height (the top) when its upward velocity becomes zero. At this point, the ball starts falling back down, and its downward velocity increases due to the force of gravity. The time it takes for the ball to reach the top is half of the total time it takes for the ball to go up and come back down.
To calculate the total time, we can use the equation for the time it takes for an object to reach its highest point and then fall back down: t_total = 2 * t_up, where t_total is the total time, and t_up is the time to reach the top.
The time to reach the top can be calculated using the equation: t_up = Δv/a, where Δv is the change in velocity (the initial velocity when the ball is thrown straight up), and a is the acceleration due to gravity.
Therefore, to compare the times going up and coming down, you need to calculate the time to reach the top and then multiply it by 2 to get the total time.