math

if x.y=30
and x+y=10.3
what is x ?

asked by layth
  1. xy=30
    (10.3-y)y=30
    y^2-10.3y+30=0
    Use the quadratic equation.
    Notice the serd: b^2-4ac is negative, so there are no real solutions.

    I wonder if you meant x/y=30
    orx=30y

    30y+y=10.3
    y=10.3/31

    posted by bobpursley

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