if x.y=30 and x+y=10.3 what is x ?

xy=30 (10.3-y)y=30 y^2-10.3y+30=0 Use the quadratic equation. Notice the serd: b^2-4ac is negative, so there are no real solutions. I wonder if you meant x/y=30 orx=30y 30y+y=10.3 y=10.3/31

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