What is the molecular, ionic and net ionic formula for Acetic acid and sodium nitrate
Molecular:
Ionic:
Net Ionic:
To determine the molecular, ionic, and net ionic formulas for acetic acid (CH3COOH) and sodium nitrate (NaNO3), we need to understand their composition and the reaction that occurs when they are mixed together.
Acetic acid (CH3COOH) consists of one carbon atom (C), two hydrogen atoms (H), and two oxygen atoms (O). It is a weak acid commonly found in vinegar.
Sodium nitrate (NaNO3) contains one sodium ion (Na+) and one nitrate ion (NO3-). It is a type of salt.
When acetic acid and sodium nitrate are mixed, a reaction called a double displacement or metathesis reaction occurs. In this reaction, the sodium ions from sodium nitrate exchange places with the hydrogen ions from acetic acid, forming sodium acetate (CH3COONa) and nitric acid (HNO3).
The molecular formula for the reaction is:
CH3COOH (acetic acid) + NaNO3 (sodium nitrate) -> CH3COONa (sodium acetate) + HNO3 (nitric acid)
The ionic formula is obtained by breaking apart the ionic compounds into their ions:
CH3COOH (acetic acid) -> CH3COO- (acetate ion) + H+ (hydrogen ion)
NaNO3 (sodium nitrate) -> Na+ (sodium ion) + NO3- (nitrate ion)
The net ionic formula includes only the ions that participate in the reaction, excluding spectator ions (ions that are present but do not undergo any change):
H+ (hydrogen ion) + Na+ (sodium ion) -> Na+ (sodium ion) + HNO3 (nitric acid)
Thus, the net ionic formula is: H+ + NO3- -> HNO3