A 1.3 kg mass accelerates at 5.8 m/s2 in a
direction 36◦ north of east. One of the two
forces acting on the mass has a magnitude of
17.3 N and is directed north.
Determine the magnitude of the second
force.
Answer in units of N.
F=ma
so figure net force from ma
then
netforce=17.3N+F
solve for F.
TO make the net force more manageable, change the acceleration to N, E components first.
Answer this qestions Aplane has an air speed of 100km/hr wind speed is 10km/hr from west.find the plane's velocity relative to ground if the pilot point the plan east?
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To find the magnitude of the second force, we need to use Newton's second law of motion, which states that the force exerted on an object is equal to its mass multiplied by its acceleration.
First, we need to find the magnitude of the total force acting on the object. We can break down this total force into its horizontal and vertical components.
The horizontal component can be found by multiplying the acceleration by the cosine of the angle between the acceleration and the positive x-axis:
Acceleration (horizontal) = acceleration * cos(θ)
= 5.8 m/s² * cos(36°)
= 4.7 m/s²
The horizontal component is directed east, so it is positive.
The vertical component can be found by multiplying the acceleration by the sine of the angle between the acceleration and the positive y-axis:
Acceleration (vertical) = acceleration * sin(θ)
= 5.8 m/s² * sin(36°)
= 3.3 m/s²
The vertical component is directed north, so it is positive.
Next, we can calculate the total force by adding the force in the horizontal direction and the force in the vertical direction:
Total force = √[(Force_horizontal)² + (Force_vertical)²]
We are given the force in the vertical direction, which is 17.3 N. So, we can plug in the values and solve for the total force:
Total force = √[(4.7 N)² + (17.3 N)²]
= √[22.09 N² + 299.29 N²]
= √321.38 N²
≈ 17.94 N
Therefore, the magnitude of the second force is approximately 17.94 N.