Two cars travel at the same constant speed. The first car travels for 10 minutes, the second for 27 minutes. If the second car travels 18 miles farther that the first, how far does each car travel?
The second car travels 17 minutes after that first car stops. During that added time, it goes 18 miles, so it is traveling 18/(17/60) = 63.5 mph
They both had the same speed when traveling.
The fist car went (1/6 hour)*63.5 = 10.58 miles
The second car went (27/60 h)(63.5) = 28.58 miles
thank you. can you help me solve another?
To solve this problem, we need to use the formula: Distance = Speed × Time.
Let's assign variables to the unknowns:
- Let's call the speed of both cars "s" (since it is constant).
- The time traveled by the first car is 10 minutes, so we'll call it "t1".
- The time traveled by the second car is 27 minutes, so we'll call it "t2".
- The distance traveled by the first car is "d1".
- The distance traveled by the second car is "d2".
From the information given, we have two important equations:
1. d2 = d1 + 18 (the second car travels 18 miles farther than the first car).
2. d1 = s × t1 and d2 = s × t2 (using the formula Distance = Speed × Time for both cars).
We need to eliminate the unknown "s" and express everything in terms of "t1" and "t2". Since the speed is the same for both cars, we can equate the two equations for "d1" and "d2":
s × t1 = s × t2
Now, let's solve this equation for "s":
s × t1 = s × t2
Divide both sides by "s":
t1 = t2
Since "t1" and "t2" are not the same, we have a contradiction. This means the information given in the question is not consistent.