2C2H6(g) + 7O2(g) > 4CO2(g) + 6H2O(g)

KCl(s) > K(s) + Cl2(g)

is this balanced?

Fist is; second is not.

To determine if the chemical equations are balanced, we need to compare the number of atoms of each element on both sides of the equation.

For the first equation, we have:

2C on the left side and 4C on the right side, which is balanced.
6H on the left side and 12H on the right side, which is not balanced.
14O on the left side and 14O on the right side, which is balanced.

To balance the hydrogen atoms, we need to multiply the coefficient in front of H2O by 2, giving us:

2C2H6(g) + 7O2(g) > 4CO2(g) + 12H2O(g)

Now, we have:

2C on the left side and 4C on the right side (balanced).
12H on the left side and 24H on the right side (balanced).
14O on the left side and 14O on the right side (balanced).

So, the first equation is balanced now.

For the second equation:

1K on the left side and 1K on the right side, which is balanced.
1Cl on the left side and 2Cl on the right side, which is not balanced.

To balance the chlorine atoms, we need to multiply the coefficient in front of Cl2 by 2, giving us:

KCl(s) > 2K(s) + Cl2(g)

Now, we have:

1K on the left side and 2K on the right side (balanced).
1Cl on the left side and 2Cl on the right side (balanced).

So, the second equation is balanced now as well.