Three Coulombs of charge flow through a wire in 150 ms.
If the current ceases to flow (goes to zero Amps) for the following 850 ms, what is the average current over this one-second period?
To determine the average current over the one-second period, we need to calculate the total charge that flows during this time and then divide it by the duration.
We are given that three Coulombs of charge flow through the wire in 150 ms. So, we need to find the charge that flows during the remaining 850 ms.
By using the relationship between charge (Q), current (I), and time (t), which is Q = I * t, we can rearrange the equation to solve for current (I).
Since the charge Q is given as three Coulombs and the time t is given as 150 ms, we can calculate the current during this time period:
I = Q / t
I = 3 C / 150 ms
To find the current during the remaining time period of 850 ms, we can subtract this initial current from zero:
I_remaining = 0 A - (3 C / 150 ms)
The average current over the one-second period is obtained by calculating the total charge (Q_total) divided by the total time (t_total):
Q_total = 3 C
t_total = 1000 ms (one second)
Now, we can calculate the average current (I_average):
I_average = Q_total / t_total
I_average = (3 C + 0 C) / 1000 ms
Converting ms to seconds (1 ms = 0.001 s):
I_average = (3 C + 0 C) / (1000 * 0.001 s)
I_average = 3 A / 1 s
Therefore, the average current over this one-second period is 3 Amperes.