Chemistry

A volume of 70.0mL of aqueous potassium hydroxide(KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the solution if 19.2mL of 1.50M H2SO4 was needed? The equation is 2KOH+H2SO4->K2SO4+2H20

asked by Peter
  1. moles H2SO4 = M x L = ??
    moles KOH = 2 x moles H2SO4.
    M KOH = moles KOH/L KOH

    posted by DrBob222
  2. vai se fuder ---- > vai tomar no cu

    posted by Anonymous
  3. 12.8

    posted by Anonymous

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