What minimum frequency of light is required to ionize potassium?The energy required to ionize potassium is 419kJ/mol?

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  1. E = h*frequency

    I would convert 419 kJ/mol to J, then divide by 6.022 x 10^23 to convert to J/atom, substitute into the equation and solve for frequency.

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  2. I got 4.6102*10^-6 and it is wrong...Can you step me through the problem?

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  3. 419 kj into jules =

    Divide by avogadro's number


    Divide that by Planck's Constant for the answer.

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  4. V=E/h so (149000/(6.026x10^-34)(6.022x10^23) =1.05x10^15. s^-1

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