Here's a physics problem. I don't care about the answer, i just want to know how to do it. don't have to be too detailed.. but i don't really kno how to start this
1.) A model rocket blasts off from the ground rising straight upward with a constant acceleration that has a magnitude of 86 m/s^2 for 1.70 seconds, at which point fuel runs out. Air resistance neglected What maximum altitude will the rocket reach?
2.)In reaching her destination, a backpacker walks with an average velocity of 1.34 m/s, due west. This average velocity of 2.68 m/s, due west,,turns around and hikes with an average velocity of 0.447 m/s due east. how far did she walk?
1. Using the acceleration and time, calculate the velocity and height at fuel burnout. Then figure the height the rocket can go above this with that initial velocity. Add the heights to get the maximum altitude.
Here is a second way.
Energy put into rocket = change in PE
Force*distance=mgh
Mass*acceleration*distance= mgh
but distance= avgvelocity*time
= (Vf/2)*time=a*t^2/2
Mass*acceleration*acceleration*t^2=mgh
h= a^2/2g * t^2 where t is the time the rocket was accelerating.
check both ways.
2.Makes no sense to me.
okay. so regarding number 1. I will use the first method. So I will calculate using this formula?
x = v0t + 1/2at^2,
in which case.. x = 86(1.70) + 1/2(-10)(1.70)^2? I get x, which would be the position.. how do figure out the height over initial velocity? do i plus 0 in for v0?
Sure! I can explain how to approach both of these physics problems.
1.) To find the maximum altitude reached by the rocket, we can use the equations of motion. We know that the rocket starts from rest (initial velocity = 0) and accelerates upward with a constant acceleration of 86 m/s^2 for 1.70 seconds. Since air resistance is neglected, we can assume that the only force acting on the rocket is gravity.
To solve this problem, we can use the following kinematic equation:
h = v_i * t + (1/2) * a * t^2
In this equation:
- h represents the maximum altitude reached by the rocket (what we're trying to find)
- v_i is the initial velocity (which is 0 in this case)
- t is the time taken (given as 1.70 seconds)
- a is the constant acceleration (which is 86 m/s^2 based on the problem statement)
By substituting the values into the equation, we can solve for h.
2.) In this problem, we need to find the total distance traveled by the backpacker. The average velocities and directions are given, so we can use the concept of average velocity to find the total distance.
The formula to calculate average velocity is:
average velocity = (total displacement) / (total time)
In this case, the backpacker walks west at an average velocity of 1.34 m/s for a certain time, turns around, and walks east at an average velocity of 0.447 m/s for another time. Since the average velocity is calculated over the entire journey, we can assume that the total displacement is zero, as the backpacker ends up at the same position.
Therefore, we can set up the following equation:
(1.34 m/s) * t1 + (-0.447 m/s) * t2 = 0
Here, t1 represents the time taken to walk west, and t2 represents the time taken to walk east.
By solving this equation, we can find the values of t1 and t2, and then calculate the total distance traveled by the backpacker as:
total distance = (1.34 m/s * t1) + (0.447 m/s * t2)
I hope this helps you understand how to approach these physics problems! Let me know if you have any more questions.