calculus




x = 6

h(x) = (x-1/2 + 5x)(1 - x-1)


asked by Jay
  1. What is the question? Are you just supposed to calculate h(6)?

    Is your h-1/2 supposed to be h^(-1/2) = 1/sqrt(h) ?

    Is the x-1 actually 1/x ?

    I looks like all you have to do is plug in 6 for x and do the calculation. That is not calculus.

    posted by drwls
  2. Im sorry ... it is a derivative question... it says to use the power rule

    posted by Jay

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