At one stage you add phosphate ion to the ractions sequence. where exactly does this phosphate end up? It is not weighed in with the copper at the end. Reaction sequence: Cu(NO3)2 = Cu(OH)2 =CuSO4 = Cu3(PO4)2= CuCl2=Cu

Duplicate posts do not a good post make. I posted a response to several of your posts earlier to the effect that you haven't provided enough information for us to know what you are doing. My best guess is that it has something to do with Cu but that's all I can guess.

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K3. Po4+s+al = ?

In the given reaction sequence, the addition of the phosphate ion (PO43-) leads to the formation of copper phosphate (Cu3(PO4)2). However, it is important to note that the phosphate ion does not contribute to the final weight of the copper because it forms a precipitate and separates from the copper compound.

Here is a breakdown of the reaction sequence:

1. Cu(NO3)2: Copper(II) nitrate dissociates into Cu2+ and NO3- ions.
2. Cu(OH)2: Copper(II) hydroxide is formed by the reaction between Cu2+ and OH- ions.
3. CuSO4: Copper(II) sulfate is produced by the reaction of Cu(OH)2 with sulfuric acid.
4. Cu3(PO4)2: Copper(II) phosphate is formed when Cu2+ ions react with phosphate (PO43-) ions. This is the step where the phosphate ion is added.
5. CuCl2: Copper(II) chloride is obtained when Cu3(PO4)2 is reacted with hydrochloric acid.
6. Cu: Finally, copper metal (Cu) is obtained by reducing CuCl2 using a suitable reducing agent.

Therefore, the phosphate ion (PO43-) ends up as copper phosphate (Cu3(PO4)2) in the reaction sequence but does not contribute to the final weight of the copper obtained.

In the given reaction sequence, where phosphate ion (PO4^3-) is added, the phosphate ions end up forming copper phosphate (Cu3(PO4)2). However, you mentioned that it is not weighed in with the copper at the end, which indicates that copper phosphate is not considered in the final result.

To understand why copper phosphate is not weighed with the copper, we need to examine the solubility properties of copper phosphate and the other compounds involved in the reactions.

Copper hydroxide (Cu(OH)2) is formed by reacting copper(II) nitrate (Cu(NO3)2) with sodium hydroxide (NaOH). Copper hydroxide is a sparingly soluble compound, which means it does not fully dissolve in water. Hence, when the reaction occurs, copper hydroxide will precipitate out as a solid.

Cu(NO3)2 + 2NaOH → Cu(OH)2 + 2NaNO3

When copper hydroxide is treated with sulfuric acid (H2SO4), it reacts to form copper sulfate (CuSO4). Copper sulfate is a soluble compound, meaning it fully dissolves in water.

Cu(OH)2 + H2SO4 → CuSO4 + 2H2O

Next, when copper sulfate is further reacted with excess phosphate ions (PO4^3-) using an appropriate phosphate source (such as sodium phosphate), copper phosphate (Cu3(PO4)2) is formed. Copper phosphate is a precipitate and like copper hydroxide, it will separate from the solution as a solid.

CuSO4 + Na3PO4 → Cu3(PO4)2 + 3Na2SO4

Now, considering copper phosphate (Cu3(PO4)2) is sparingly soluble, it should weigh with the copper in the final result. However, if you observed that it is not weighed with the copper, one possibility is that it was not fully precipitated and hence remained in the solution. Another possibility is that a separation step was involved after the formation of copper phosphate to remove any excess copper phosphate from the solution before weighing the copper.

To determine the exact reasoning behind not weighing the copper phosphate, it would be helpful to provide further information about the experimental procedure or context in which this reaction sequence is being conducted.