Consider a region in space where a uniform electric field E = 7450 N/C points in the negative x direction. What is the distance between the +13.1 V and the +14.1 V equipotentials?
To find the distance between equipotentials, you need to first understand the concept of equipotential surfaces.
Equipotential surfaces are imaginary surfaces in an electric field where the electric potential is the same everywhere on that surface. In other words, all points on an equipotential surface have the same electric potential.
In this case, we're given a uniform electric field of E = 7450 N/C pointing in the negative x direction. To find the distance between the +13.1 V and the +14.1 V equipotentials, we can use the equation:
ΔV = -E * Δd
where ΔV is the potential difference between the equipotential surfaces, E is the magnitude of the electric field, and Δd is the distance between the equipotentials.
Rearranging the equation, we can solve for Δd:
Δd = ΔV / (-E)
Now, substitute the given values:
ΔV = (+14.1 V) - (+13.1 V) = 1.0 V
E = 7450 N/C
Δd = 1.0 V / (-7450 N/C)
Note that the negative sign is used because the electric field points in the negative x direction.
Calculating Δd:
Δd = -1.0 V / 7450 N/C
After performing the calculation, you can find the distance between the +13.1 V and the +14.1 V equipotentials in the given electric field.