4 digit number greater than 8000 disvible by 5 sum of all digits equals 20?
There could be many numbers.
8075
Remember that any number ending with 5 or 0 is divisible by 5.
other clues are tens digit is 1 less than thousands and tens digit is 2 more than ones
To find a 4-digit number greater than 8000 that is divisible by 5 and has a sum of digits equal to 20, we can follow these steps:
Step 1: Start by finding the smallest 4-digit number greater than 8000 that is divisible by 5. Since the number must be divisible by 5, the last digit must be either 0 or 5. Based on the given conditions, we can conclude that the last digit must be 5 to have a sum of digits equal to 20.
Step 2: To satisfy the condition of a sum of digits equal to 20, we need to distribute the remaining sum of 15 among the first three digits. Since each digit can range from 0 to 9, the sum of the first three digits should be between 0 and 27.
Step 3: We can start by assigning the maximum possible value to the first digit, which is 9. This leaves us with a remaining sum of 11 to distribute among the second and third digits.
Step 4: Since the sum of the second and third digits should be equal to 11, we can try different combinations to find a solution. For example, we can assign the value 9 to the second digit and 2 to the third digit, making the sum equal to 9 + 9 + 2 = 20.
Therefore, the 4-digit number greater than 8000, divisible by 5, and having a sum of digits equal to 20 is 9255.