calculate the specific heat (j/g C ) for each of the following:
-an 18.5-g sample of tin that absorbs 183 J when its temperature inceases from 35.0 degrees C to 78.6 degrees C
q = mass x specific heat x delta T.
thank you
To calculate the specific heat, we can use the formula:
q = m * c * ΔT
Where:
q is the heat energy absorbed or released by the substance (in this case, 183 J).
m is the mass of the substance (18.5 g).
c is the specific heat capacity of the substance (what we need to find).
ΔT is the change in temperature (78.6 °C - 35.0 °C = 43.6 °C).
Rearranging the formula, we can solve for c:
c = q / (m * ΔT)
Plugging in the values:
c = 183 J / (18.5 g * 43.6 °C)
Now, let's calculate the specific heat:
c = 183 J / (805.6 g·°C)
Simplifying, we get:
c ≈ 0.227 J/g°C
Therefore, the specific heat (c) for the 18.5-g sample of tin is approximately 0.227 J/g°C.