log(5x+1)=2+log(2x-3)
log(5x+1)-log(2x-3)=2
(5x+1)/(2x-3)=10^2
what do i do after that?
you could cross multiply.
(5x+1)/(2x-3)=(10^2)/1
(5x+1)=(2x-3)(10^2)
i have to figure out what x is
yes
After simplifying the expression to (5x+1)/(2x-3)=100, you can proceed to solve for x by isolating the variable on one side of the equation.
To do this, you can multiply both sides of the equation by (2x-3) to eliminate the denominator:
(5x+1)/(2x-3) * (2x-3) = 100 * (2x-3)
This results in:
5x + 1 = 100(2x - 3)
Next, distribute the 100 on the right side of the equation:
5x + 1 = 200x - 300
Now, move all the terms involving x to one side and the constants to the other side:
5x - 200x = -300 - 1
Combine like terms:
-195x = -301
Finally, isolate x by dividing both sides of the equation by -195:
x = -301 / -195
Simplifying the fraction on the right side gives you the value of x:
x = 301/195
Therefore, the solution to the equation is x ≈ 1.544.