SOLVE BY SUBSTITUTION MATH...8X+5Y=-7

X=36-8Y

Do exactly what it says ...

8X+5Y=-7
8(36-8Y) + 5Y = -7

solve for Y, then sub that back into your second equation.
I am sure you can take it from here

8X + 5Y = -7

X = 36 - 8Y
Substitute 36 - 8y for x in 1st Eq:
8(36 - 8y) + 5y = -7,
288 - 64y + 5y = -7,
-64y + 5y = -7 -288,
-59y = - 295,
y = -295/-59 = 5.
Substitute 5 for y in the 2nd Eq:
X = 36 - 8 * 5 = -4.

Solution set: (-4 , 5).

To solve the given system of equations using the substitution method, we can substitute the value of x from the second equation into the first equation.

Given equations:
1) 8x + 5y = -7
2) x = 36 - 8y

Substitute the value of x from equation 2 into equation 1:
8(36 - 8y) + 5y = -7

Simplify the equation:
288 - 64y + 5y = -7
Combine like terms:
-59y + 288 = -7

Move the constant term to the other side of the equation:
-59y = -7 - 288
-59y = -295

Divide both sides by -59 to isolate y:
y = (-295) / (-59)
y = 5

Now that we have the value of y, substitute it back into the second equation to find the value of x:
x = 36 - 8y
x = 36 - 8(5)
x = 36 - 40
x = -4

Therefore, the solution to the system of equations is x = -4 and y = 5.