SOLVE THE SYSTEM USING SUBSTITUTION MATH X-4Y=49 3Y-4Y=-66

Check your second equation again. It has two "Y" terms.

Did you substitute a Y for an X?

i have redone this problem over and over and i just cant seem to get it..

You did not read or understand my comment.

The equation 3Y - 4Y = -66 has probably been typed incorrectly by you.

To solve the given system of equations using substitution, we will first rearrange one equation to express one variable in terms of the other variable, and then substitute this expression into the second equation.

Let's start with equation 1:
X - 4Y = 49

To express X in terms of Y, we can add 4Y to both sides of the equation:
X = 49 + 4Y

Now let's substitute this expression for X into equation 2:
3Y - 4X = -66

Substituting the value of X, we have:
3Y - 4(49 + 4Y) = -66

Next, distribute the -4 to each term within the parentheses:
3Y - 196 - 16Y = -66

Combine like terms:
-13Y - 196 = -66

To isolate Y, we can move the constant term to the other side by adding 196 to both sides of the equation:
-13Y = -66 + 196
-13Y = 130

Then, divide both sides of the equation by -13 to solve for Y:
Y = 130 / -13
Y = -10

Now that we have found the value of Y, we can substitute it back into either of the original equations to solve for X. Let's use equation 1:
X - 4(-10) = 49
X + 40 = 49

Subtract 40 from both sides:
X = 49 - 40
X = 9

Therefore, the solution to the system of equations is X = 9 and Y = -10.