A man lifts a 2.0 kg stone vertically with his hand at a constant upward velocity of 1.5 m/s. What is the magnitude of te total force of the stone on the man's hand?
The weight, M g.
No extra force is needed becasue it is not acclerating.
1.56
20N
23
To find the magnitude of the total force exerted on the man's hand by the stone, we can use Newton's second law of motion. According to this law, the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
In this case, the stone is moving with a constant velocity of 1.5 m/s in the upward direction, which means it is not accelerating. Therefore, the net force acting on the stone is zero. But since the stone is being lifted, there must be an equal and opposite force acting on the man's hand to support the weight of the stone.
The weight of an object can be calculated by multiplying its mass by the acceleration due to gravity. On Earth, the acceleration due to gravity is approximately 9.8 m/s^2.
So, the weight of the stone is given by:
Weight = mass x acceleration due to gravity
Weight = 2.0 kg x 9.8 m/s^2
Weight = 19.6 N
Since the stone is being lifted at a constant velocity, the magnitude of the total force of the stone on the man's hand is equal to the weight of the stone, which is 19.6 Newtons.