Question

An object with constant acceleration has velocity v = 12 m/s when it is at x = 6 m and v = 17 m/s when it is at x = 10 m. What is its acceleration?

Answer 1

Vfinal^2 - Vinitial^2 = 2 a (Xfinal - Xinitial)

Solve for a

289 - 144 = 2*a*(10 - 6)