A truck has to travel at what speed to stay underneath an airplane traveling at 105 kg/h at 25% angle to the ground.
Speed is not meaured in kilograms per hour. I assume you meant kilomets per hour.
Do you mean a 25% angle or a 25 degree angle? A 25% slope would be 14.04 degrees. The slope is the tangent of the angle.
Whatever the angle is, call it A.
The truck speed would have to be
(105 km/h)*cosA
To answer this question, we need to consider the speed and angle of the airplane, as well as the relative position of the truck and the airplane.
First, let's convert the airplane's speed from kilometers per hour (km/h) to meters per second (m/s). Since there are 1000 meters in a kilometer and 3600 seconds in an hour, we can use the conversion factor:
105 km/h * (1000 m/km) / (3600 s/h) = 29.16 m/s (approx)
Now, let's assume that the truck is traveling directly underneath the airplane, parallel to the ground. In this case, the truck's speed must be equal to the horizontal component of the airplane's velocity to stay underneath it.
The horizontal component of the airplane's velocity can be found by multiplying the airplane's speed by the cosine of the angle it makes with the ground. Since the angle is given as 25%, we can calculate the cosine using a scientific calculator or online tool:
cos(25°) ≈ 0.9063
Now we can find the truck's speed:
Truck speed = Horizontal component of the airplane's speed
= Airplane speed * cos(Plane's angle to the ground)
≈ 29.16 m/s * 0.9063
≈ 26.45 m/s (approx)
Therefore, the truck needs to travel at approximately 26.45 meters per second to stay underneath the airplane.