1. Many people know that the weight of an object varies on different planets, but did you know that the weight of an object on Earth also varies according to the elevation of the object? In particular, the weight of an object follows this equation: , where C is a constant, and r is the distance that the object is from the center of Earth.

Your equation is inpt shown.

It should be something like:
W = C M/r^2
where r ais the distance mentioned, M is the mass of the object (which does not depend upon gravity) and C is a constant.

You have not asked a question, either.

To understand why the weight of an object on Earth varies with elevation, we need to consider the concept of gravitational force. Gravitational force is the force of attraction between two objects due to their masses. On Earth, the force of gravity is what gives objects weight.

The weight of an object is determined by the gravitational force acting on it. The force of gravity depends on two factors: the mass of the object and the distance between the object and the center of the Earth.

The equation you provided, W = C/r^2, represents the relationship between weight and distance from the center of the Earth. Here, W represents the weight of the object, C is a constant, and r is the distance between the object and the center of the Earth.

As the distance from the center of the Earth increases (i.e., as you move away from the surface), the value of r increases, and hence, the weight of the object decreases. This is because the force of gravity decreases as the distance between the object and the center of the Earth increases.

Conversely, as the object moves closer to the surface, the value of r decreases, and the weight of the object increases. This is because the force of gravity becomes stronger as the object gets closer to the center of the Earth.

It is worth noting that the equation you provided is a simplified representation and does not take into account other factors such as the Earth's rotation and the variation in gravitational acceleration due to the shape of the Earth. However, for most practical purposes, this simplified equation can provide a reasonable approximation.