Carbon monoxide gas reacts with oxygen gas to form carbon dioxide gas acooridng to the following equation:
2CO(g)+O2(g)--> 2 CO2(g)
IF 1 mole of CO2(g) is produves, how many kilojoules of heat energy are absorbed or released ?
2mol
To determine the amount of heat energy absorbed or released in a chemical reaction, you need to know the enthalpy change (∆H) associated with the reaction. The value of ∆H will be given in kilojoules (kJ) per mole, indicating the amount of heat energy exchanged per mole of reactants or products.
Since the equation you provided does not include any specific enthalpy values, we cannot directly determine the heat energy released or absorbed. However, if the question assumes that the reaction is occurring under standard conditions and if the ∆H° value is known, we can use it to solve the problem.
If we assume that the reaction occurs under standard conditions (∆H°) and the value is, for example, -394 kJ/mol (the enthalpy change of combustion of carbon monoxide), we can use stoichiometry to determine the heat energy released or absorbed for the given mole of carbon dioxide (CO2) produced.
From the balanced equation: 2CO(g) + O2(g) --> 2CO2(g), we can see that for every 2 moles of carbon monoxide (CO) reacted, we produce 2 moles of carbon dioxide (CO2).
Therefore, if 1 mole of CO2(g) is produced, it means that 1 mole of CO(g) reacted.
Using the stoichiometry and the ∆H° value of -394 kJ/mol, we can calculate the heat energy released or absorbed as follows:
Heat energy = ∆H° × (moles of CO2 produced)
Heat energy = -394 kJ/mol × 1 mole
= -394 kJ
Since the coefficient in front of CO2 in the balanced equation is 2, we need to double the result:
Heat energy = -394 kJ × 2
= -788 kJ
Therefore, if 1 mole of CO2 is produced in the reaction and the ∆H° value is -394 kJ/mol, the reaction will release 788 kilojoules (kJ) of heat energy.