can someone show me how to graph
y+1=-3/2(x-0)
Will this help?
y+1=-3/2(x-0)
y+1=-3/2(x)
y=-3/2(x)-1
When x=0, y=-1
When x=1, y=-5/2
When x=2, y=-4
and so on.
set it up like y=mx+b:
y=-3/2x-1
b=y-intercept
m=slope
put a dot at (0,-1) that is the y-intercept
then go down three and right two (or up three and left two) [that's the slope: -3/2]
Certainly! I can help you with that.
The given equation is in slope-intercept form (y = mx + b), where m represents the slope of the line and b is the y-intercept. To graph the equation y + 1 = -3/2(x - 0), we first need to rearrange it into slope-intercept form.
Step 1: Distribute the -3/2 to the terms in the parentheses:
y + 1 = -3/2 * x - 0
Step 2: Simplify the equation by multiplying -3/2 with x:
y + 1 = -3/2x
Step 3: Add 1 to both sides of the equation to isolate y:
y = -3/2x - 1
Now that we have rewritten the equation in slope-intercept form, we can easily identify the slope and y-intercept.
The slope (m) is the coefficient of x, which is -3/2. The y-intercept (b) is the constant term, which is -1.
To graph the equation, follow these steps:
1. Plot the y-intercept first. In this case, the y-intercept is located at (0, -1).
2. From the y-intercept, use the slope to find additional points on the line. Since the slope is -3/2, it means that for every 2 units moved in the horizontal direction (to the right), we need to move 3 units in the vertical direction (up or down). Use this information to plot more points on the line.
3. Once you have multiple points, connect them to draw the line. Make sure the line extends beyond the plotted points to show its direction.
Here's an example of how the graph would look like when you plot the points and draw the line:
|
|
| (0, -1)
|
|
|
+----------------------------------