geometry

T is in the interior of angle"PQR". if angle"PQR"=10X-7, angle"RQT"=5X and angle"PQT"=4x+6 "X" will eaqual to?

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  1. PQT + RQT = PQR,
    (4X + 6) + 5X = 10X - 7,
    4X + 5X - 10X = -7 - 6,
    -X = -13,
    X = 13.

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  2. why its 13 i didn't get it could u give me several steps

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  3. Par

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  4. My question is a bit different then this

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