How many uranium atoms are there in 8.4 g of pure uranium? The mass of one uranium atom is 4 x 10^-26
kg for the 4 x 10^-26
number atoms * mass of one= total mass
solve for the number of atoms.
To calculate the number of uranium atoms in 8.4 g of pure uranium, we can use the concept of molar mass and Avogadro's number.
First, we need to calculate the molar mass of uranium (U). Uranium has an atomic mass of approximately 238.03 grams per mole (g/mol).
Next, we can use the molar mass to convert grams of uranium to moles of uranium. This can be done by dividing the given mass by the molar mass of uranium:
8.4 g / 238.03 g/mol = 0.0353 moles of uranium
Now, to find the number of atoms, we can use Avogadro's number. Avogadro's number represents the number of atoms in one mole of a substance, which is approximately 6.022 x 10^23 atoms/mol.
0.0353 moles of uranium x (6.022 x 10^23 atoms/mol) = 2.12 x 10^22 uranium atoms
Therefore, there are approximately 2.12 x 10^22 uranium atoms in 8.4 g of pure uranium.