1. At 11:00 a.m. a one-meter-high mailbox casts a 0.7-meter shadow. If a pole beside the mailbox casts a 28-meter shadow, how tall is that pole?

400 m
40 m
0.4 m
4 m

A Squared + B squared = C squared

I don't understand.????

The Pythagorean theorem is not needed here.

They are proportional.

1/.7 = x/28

Multiply both sides by 28.

28/.7 = x = ?

40 m

To find the height of the pole, we can use the property of similar triangles. Here's how to solve the problem step by step:

1. Start by setting up a proportion between the height of the mailbox and its shadow length:
mailbox height / mailbox shadow length = pole height / pole shadow length

2. Substitute the given values into the proportion:
1 meter / 0.7 meter = x / 28 meters

Simplify the proportion:
1.4286 = x / 28

3. Cross-multiply to solve for x (the height of the pole):
1.4286 * 28 = x
x ≈ 39.9992 meters

Since x represents the height of the pole, we can approximate it to 40 meters. Therefore, the answer is 40 m.