Justify your answer:

1.) Which line is steeper?
y= 4/3x - 5 or y= 6/5x - 1

2.) Does the slope of line AB exist?
A (-2,7) B (-2,-1)

1.) To determine which line is steeper, we need to compare the slopes of the two lines. The slope-intercept form of a linear equation is given by y = mx + b, where m represents the slope.

For the first equation, y = (4/3)x - 5, the slope is 4/3.

For the second equation, y = (6/5)x - 1, the slope is 6/5.

To compare the slopes, we need to find a common denominator. In this case, the common denominator is 15.

Converting the slopes to have a denominator of 15, we get 20/15 (4/3 as a fraction with a denominator of 15) and 18/15 (6/5 as a fraction with a denominator of 15).

Comparing the two fractions, 20/15 > 18/15.

Therefore, the line y = 4/3x - 5 is steeper compared to y = 6/5x - 1.

2.) To determine if the slope of line AB exists, we need to check if the x-coordinates of points A and B are the same.

Given that point A is (-2,7) and point B is (-2,-1), we can see that the x-coordinates of both points are identical.

When two points have the same x-coordinate, the line passing through them will be vertical or have an undefined slope. This means that the slope does not exist for line AB.

Therefore, the slope of line AB does not exist.