calculate the calories needed at 0 C to melt 200. g of ice
Heat= massice*LatentheatofFusion
The latent heat of fusion of ice is 80cal/gram, or 334joules/gram
To calculate the calories needed to melt 200 grams of ice at 0°C, we can use the following formula:
Q = m * L
Where:
Q = heat energy required (in calories)
m = mass of the substance (in grams)
L = heat of fusion (latent heat) of the substance (in calories/gram)
The heat of fusion, or latent heat, for ice is 79.7 calories/gram.
Plugging in the values:
Q = 200 g * 79.7 cal/g
Q = 15,940 calories
Therefore, it would require approximately 15,940 calories to melt 200 grams of ice at 0°C.
To calculate the calories needed to melt 200 g of ice at 0°C, we need to use the formula for heat transfer, which is given by:
Q = m * ΔHf
where:
Q is the heat energy (in calories)
m is the mass of the substance that is changing phase (in grams)
ΔHf is the heat of fusion, which represents the amount of heat required to change the substance from solid to liquid (in calories per gram)
In the case of ice, the heat of fusion, ΔHf, is 79.7 calories per gram.
Now, let's substitute the values into the formula:
Q = 200 g * 79.7 calories/g
Calculating:
Q = 15,940 calories
Therefore, it takes approximately 15,940 calories to melt 200 g of ice at 0°C.