for the reaction ZnO + 2HCl yields ZnCL2 + H2O, what is the maximum amount of ZnCl2 which could be formed from 17.24 grams of ZnO and 6.87 grams of HCl?
answer in units of grams.
Here are the steps to work the problem.
See the SECOND response, not the first.
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To find the maximum amount of ZnCl2 that could be formed from 17.24 grams of ZnO and 6.87 grams of HCl, we need to determine which reactant is limiting and then calculate the amount of ZnCl2 produced based on the limiting reactant.
Let's start by calculating the number of moles of each reactant:
1. Determine the molar mass of ZnO (Zinc Oxide):
- The atomic mass of Zinc (Zn) is 65.38 g/mol.
- The atomic mass of Oxygen (O) is 16.00 g/mol.
- Therefore, the molar mass of ZnO = (1 x 65.38 g/mol) + (1 x 16.00 g/mol) = 81.38 g/mol.
Number of moles of ZnO = Mass of ZnO / Molar mass of ZnO
= 17.24 g / 81.38 g/mol
≈ 0.212 moles of ZnO.
2. Determine the molar mass of HCl (Hydrochloric Acid):
- The atomic mass of Hydrogen (H) is 1.01 g/mol.
- The atomic mass of Chlorine (Cl) is 35.45 g/mol.
- Therefore, the molar mass of HCl = (1 x 1.01g/mol) + (1 x 35.45 g/mol) = 36.46 g/mol.
Number of moles of HCl = Mass of HCl / Molar mass of HCl
= 6.87 g / 36.46 g/mol
≈ 0.188 moles of HCl.
3. Using the balanced equation, we can determine the stoichiometry of the reaction:
ZnO + 2HCl → ZnCl2 + H2O
From the equation, we can see that 1 mole of ZnO reacts with 2 moles of HCl to produce 1 mole of ZnCl2. Therefore, the molar ratio of ZnO to ZnCl2 is 1:1.
4. Determine the limiting reactant:
The reactant that produces the lowest amount of product is the limiting reactant.
Since the molar ratio of ZnO to ZnCl2 is 1:1, and the number of moles of ZnO (0.212 moles) is greater than the number of moles of HCl (0.188 moles), the limiting reactant is HCl.
5. Calculate the theoretical yield of ZnCl2:
Theoretical yield of ZnCl2 = Number of moles of limiting reactant x Molar mass of ZnCl2
Number of moles of ZnCl2 = Number of moles of HCl (since the molar ratio is 1:1)
= 0.188 moles.
Molar mass of ZnCl2 = (1 x 65.38 g/mol) + (2 x 35.45 g/mol) = 136.28 g/mol.
Theoretical yield of ZnCl2 = 0.188 moles x 136.28 g/mol
≈ 25.66 grams.
Therefore, the maximum amount of ZnCl2 that can be formed from 17.24 grams of ZnO and 6.87 grams of HCl is approximately 25.66 grams.