If you are making 430.0 g of 0.41 m Na2SO3, how many grams of the solute should you use?
I got 20 grams, but I don't think this is the right answer.
1m = 1 mole/kg solvent
moles = m x kg
moles = 0.41 x 0.430 kg = 0.1763 moles.
moles = grams/molar mass or
g = moles x molar mass = 0.1763 x 136 = 23.9768 which rounds to 24 g to two significant figures.