math
 👍
 👎
 👁
Respond to this Question
Similar Questions

Algebra
Consider the following polynomial function F(x)=2x^3x^2+13x6 to answer the following question. If (x+3) is a factor of f(x) rewrite f(x) in completely factored form and identify the zeros f(x).

Algebra 2 (Please help Ms. Sue!)
Use synthetic division and the given factor to completely factor the polynomial. x^3x^224x36; (x6) How do I do this?

Math
Write the polynomial as a product of linear factors (in completely factored form) given x + 2 is a factor. p(x) = 3x^4 + 4x^3  x^2 + 4x  4 please help me =,(

Algebra 1Factoring Help!
Factor completely. if the polynomial is prime, state this. 6x^221x9 I am confused about how to factoring. Thanks!

Math
Part 1: Suppose you divide a polynomial by a binomial. How do you know if the binomial is a factor of the polynomial? Create a sample problem that has a binomial which IS a factor of the polynomial being divided, and another

math help
Factor f(x) into linear factors given that k is a zero of f(x). f(x)=x^3+(124i)x^2+(3248i)x128i, k=4i In completely factored form, f(x) =____ (factor completely. simplify your answer)

Math
Factor the polynomial as the product of factors that are irreducible over the real numbers. Then write the polynomial in completely factored form involving complex nonreal or imaginary numbers. x^4 + 20x^2 44=0

algebra 1
Factor the polynomial expression. Write each factor as a polynomial in descending order. Enter exponents using the caret ( ^ ). For example, you would enter x2 as x^2. 44x^3+36x^2

Algebra
What is 9x^2 +4x^2 Factor each polynomial completely. If a polynomial is prime, say so.

Algebra
Factor polynomial completely ax  2a  5x +10

algebra
Factor the polynomial completely 3m^2 75 This is how I started to work it out. (3m23)(m5)

Maths
When the polynomial f(x)=(p1)+x^3+px^2+qx+r, where p, q is divided by (x+2) and (x1) the remainders are 5 and 4 respectively. If (x+1) is a factor of f(x), find the value of p, q and r, hence factorize f(x) completely.
You can view more similar questions or ask a new question.