A bike accelerates from 0.0 m/s to 4.1 m/s in 6 s. What distance does it travel?
thanks for the help
See:
http://www.jiskha.com/display.cgi?id=1283904514
To find the distance traveled by the bike, we can use the equation:
distance = initial velocity * time + 0.5 * acceleration * time^2
Given:
Initial velocity (u) = 0.0 m/s
Final velocity (v) = 4.1 m/s
Time (t) = 6 s
First, we need to calculate the acceleration (a) using the formula:
acceleration = (final velocity - initial velocity) / time
Substituting the given values:
acceleration = (4.1 m/s - 0.0 m/s) / 6 s
acceleration = 0.683333 m/s^2
Now, we can use the equation to find the distance:
distance = 0.0 m/s * 6 s + 0.5 * 0.683333 m/s^2 * (6 s)^2
distance = 0 + 0.5 * 0.683333 m/s^2 * 36 s^2
distance = 0 + 0.5 * 0.683333 m/s^2 * 36 s^2
distance = 0.5 * 0.683333 m/s^2 * 36 s^2
distance = 0.5 * 0.683333 * 36
distance = 0.5 * 24.59999
distance = 12.29999 m
Rounding to the appropriate number of significant figures, the bike travels approximately 12.3 meters.