A ball is dropped from a cliff and has an acceleration of 9.8 m/s2. How long will it take the ball to reach a speed of 24.5 m/s?
We can use the formula for acceleration:
a = (v - u) / t
where a is acceleration, v is the final velocity, u is the initial velocity, and t is time. Since the ball is dropped, u = 0. We want to find t, so we can rearrange the formula:
t = (v - u) / a
Plugging in the values:
t = (24.5 m/s - 0 m/s) / 9.8 m/s^2
t = 24.5 m/s / 9.8 m/s^2
t ≈ 2.5 seconds
The ball will take approximately 2.5 seconds to reach a speed of 24.5 m/s.
To find out how long it will take for the ball to reach a speed of 24.5 m/s, we can use the formula:
v = u + at
Where:
v = final velocity (24.5 m/s)
u = initial velocity (0 m/s, as the ball is being dropped)
a = acceleration (9.8 m/s²)
t = time (unknown)
Rearranging the formula to solve for time (t), we have:
t = (v - u) / a
Substituting the known values:
t = (24.5 m/s - 0 m/s) / 9.8 m/s²
Calculating:
t = 24.5 m/s / 9.8 m/s²
t ≈ 2.5 seconds
So, it will take approximately 2.5 seconds for the ball to reach a speed of 24.5 m/s.
To find the time it takes for the ball to reach a speed of 24.5 m/s, we can use the equation:
v = u + at
Where:
v = final velocity (24.5 m/s)
u = initial velocity (0 m/s, as the ball is dropped)
a = acceleration (9.8 m/s^2)
t = time
Rearranging the equation gives us:
t = (v - u) / a
Substituting the given values into the equation:
t = (24.5 m/s - 0 m/s) / 9.8 m/s^2
Simplifying, we get:
t = 24.5 m/s / 9.8 m/s^2
Now, we can calculate the time it takes for the ball to reach a speed of 24.5 m/s:
t = 2.5 seconds
Therefore, it will take the ball 2.5 seconds to reach a speed of 24.5 m/s.