i need to find when the function increases or decreases, this is the derivative of the function
(10 − 3x)/(2 ¡î5 − x)
but how do you solve the function when x is zero?
To solve the function when x is zero, we need to substitute x = 0 into the given derivative and determine its value. Let's go step by step:
1. Start with the given derivative function: f'(x) = (10 - 3x)/(2√(5) - x)
2. Substitute x = 0 into f'(x) to find the value when x is zero:
f'(0) = (10 - 3(0))/(2√(5) - 0)
= 10/(2√(5))
= 5/√(5)
= 5 * √(5)/5
= √(5)
Therefore, when x is zero, the value of the derivative function is √(5).