A jogger accelerates from rest to 2.7 m/s in 2.2 s. A car accelerates from 39.0 to 44.0 m/s also in 2.2 s.

(a) Find the acceleration (magnitude only) of the jogger.

(b) Determine the acceleration (magnitude only) of the car.

(c) Does the car travel farther than the jogger during the 2.2 s?

Yes
No
Equal

If so, how much farther?
m

To find the acceleration of an object, you can use the equation:

acceleration = (final velocity - initial velocity) / time

For the jogger:
(a) The jogger's initial velocity is 0 m/s (since the jogger starts from rest), the final velocity is 2.7 m/s, and the time is 2.2 s. Substituting these values into the equation:

acceleration = (2.7 m/s - 0 m/s) / 2.2 s = 1.227 m/s²

So, the magnitude of the jogger's acceleration is 1.227 m/s².

For the car:
(b) The car's initial velocity is 39.0 m/s, the final velocity is 44.0 m/s, and the time is 2.2 s. Substituting these values into the equation:

acceleration = (44.0 m/s - 39.0 m/s) / 2.2 s = 2.273 m/s²

So, the magnitude of the car's acceleration is 2.273 m/s².

To determine whether the car travels farther than the jogger during the 2.2 s, we need to compare their displacements. The displacement of an object with constant acceleration can be determined using the equation:

displacement = (initial velocity * time) + (0.5 * acceleration * time²)

For the jogger:
initial velocity = 0 m/s (since the jogger starts from rest)

displacement_jogger = (0 m/s * 2.2 s) + (0.5 * 1.227 m/s² * (2.2 s)²) = 2.692 m

For the car:
initial velocity = 39.0 m/s

displacement_car = (39.0 m/s * 2.2 s) + (0.5 * 2.273 m/s² * (2.2 s)²) = 99.42 m

Since the displacement of the car (99.42 m) is greater than the displacement of the jogger (2.692 m), the car travels farther than the jogger during the 2.2 s.

2.7 / 2.2

(44-39)/2.2

The car was going 39 m/s at the beginning and speeded up during the 2.2 s
The jogger never got going more than 2.7 m/s
Which went further during the 2.2 s ? LOL

jogger d = (1/2 )(acceleration from part a) * 2.2^2

car d = 39*2.2 + (1/2) (accelration of car from part b) *2.2^2