Calculate the amount of heat required to heat 80 grams of water from 10 to 53°C. The specific heat capacity for water is 4.184 J/g°C.
It takes 4.184 J to heat 1 g of water 1 degree C. How much to heat 80 g water 1 degree C?
Then how much to heat 80 g water (53-10) degrees C?
You can also look at the units. You know 4.184 = J/gC Solve this algebraically with your known g (number of grams) and your known C (change in degrees C). solve for J.
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To calculate the amount of heat required to heat a substance, we can use the formula:
Q = m * c * ΔT
Where:
Q = amount of heat (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g°C)
ΔT = change in temperature (in °C)
For this question, we have:
m = 80 grams
c = 4.184 J/g°C
ΔT = (53 - 10) °C
Substituting the values into the formula, we get:
Q = 80 * 4.184 * (53 - 10)
Simplifying the equation further:
Q = 80 * 4.184 * 43
Calculating the value:
Q ≈ 14,391.04 joules
Therefore, the amount of heat required to heat 80 grams of water from 10 to 53°C is approximately 14,391.04 joules.