Naturally occuring chlorine gas has 3 isotopes
35cl-35cl, 35cl-37cl , 37cl-37cl
a) mass of one molecule in terms of amu.
b) mass of one molecule in terms of grams.
c) mass of one mole in terms of grams.
d) Naturally occuring Cl has 75% 35cl and 25% 37cl, calculate the mass of one mole of cl(small 2) gas.
--I didn't really understood these as i am in prep chem and i guess my teacher is too stupid to understand that. He gave us this on first pop quiz when our first chapter was about conversions and basic stuff. Please help or get me started on this at least.
I read your question when you posted earlier and I don't uhderstand anything about 35cl-35cl, 35cl-37cl, 37cl-37cl. If you can explain what that is perhaps someone can help.
d,Atomic mass= fraction of the isotope X mass of the isotope.
I'm sorry to hear that you're having trouble with this question on your pop quiz. I'll do my best to explain it to you step by step so you can understand and solve it.
Chlorine gas has three naturally occurring isotopes: 35Cl-35Cl, 35Cl-37Cl, and 37Cl-37Cl. To answer the given questions, we need to understand the concepts of atomic mass units (amu), grams, moles, and percent composition.
a) The atomic mass unit (amu) is a unit of mass used to express the mass of atoms or molecules. We need to calculate the mass of one molecule in terms of amu.
To calculate the mass of one molecule, we need to know the atomic masses of the isotopes present in the molecule and their abundances.
The atomic mass of an isotope is the weighted average of the masses of all its isotopes, taking into account their relative abundances (%).
The atomic masses of the isotopes are:
- 35Cl: 35.0 amu
- 37Cl: 37.0 amu
The abundances of the isotopes are given: 75% 35Cl and 25% 37Cl.
To calculate the mass of one molecule, we use the weighted average formula:
Mass of one molecule = (Abundance1 × Mass1) + (Abundance2 × Mass2) + ...
Plugging in the values:
Mass of one molecule = (0.75 × 35.0 amu) + (0.25 × 37.0 amu)
b) To find the mass of one molecule in terms of grams, we need to convert the mass from amu to grams.
1 amu is equal to 1.66053906660 x 10^-24 grams. So we can convert the mass of one molecule from amu to grams by multiplying it by this conversion factor.
c) To find the mass of one mole of chlorine gas in grams, we need to multiply the mass of one molecule (in grams) by Avogadro's number, which is approximately 6.022 x 10^23 molecules in one mole.
Mass of one mole of chlorine gas = Mass of one molecule (in grams) x Avogadro's number
d) The last part of the question asks you to calculate the mass of one mole of chlorine gas knowing that it has 75% 35Cl and 25% 37Cl.
To calculate the mass of one mole of chlorine gas, we can use the same formula as in part c), but with the calculated mass of one molecule (in grams) for the chlorine gas.
I hope this explanation helps you understand the problem and how to approach it. Let me know if you have any further questions!