Balance in acid solution
PH3+ I2-> H3PO4+ I-
To determine the balanced chemical equation for the reaction between PH3 and I2 to form H3PO4 and I-, you need to follow these steps:
Step 1: Write down the unbalanced equation.
PH3 + I2 → H3PO4 + I-
Step 2: Balance the atoms other than hydrogen (H) and oxygen (O). In this reaction, we have phosphorus (P) and iodine (I) that need to be balanced.
Balance the phosphorus atom:
PH3 + I2 → H3PO4 + I-
To balance the phosphorus, add a coefficient of 4 in front of the H3PO4:
PH3 + I2 → 4H3PO4 + I-
Balance the iodine atom:
PH3 + I2 → 4H3PO4 + 5I-
Now, the phosphorus and iodine atoms are balanced.
Step 3: Balance the hydrogen (H) and oxygen (O) atoms using water (H2O).
Count the number of hydrogen (H) and oxygen (O) atoms on each side of the equation:
Left side: 3H (from PH3) + 4H (from H3PO4) = 7H
Right side: 5H (from H2O in H3PO4) = 5H
Since there are more hydrogen atoms on the left side, we need to add water (H2O) molecules to balance the hydrogen:
PH3 + I2 + 3H2O → 4H3PO4 + 5I-
The number of hydrogen atoms is now balanced.
Count the number of oxygen (O) atoms on each side of the equation:
Left side: 0O
Right side: 12O (from 4H3PO4)
Since there are no oxygen atoms on the left side, we need to add oxygen (O2) molecules:
PH3 + I2 + 3H2O + 6O2 → 4H3PO4 + 5I-
The number of oxygen atoms is now balanced.
Step 4: Check if all the atoms are balanced:
Left side: 1P, 5I, 10H, 6O
Right side: 4P, 5I, 16H, 12O
All the atoms are now balanced.
The balanced equation is:
PH3 + I2 + 3H2O + 6O2 → 4H3PO4 + 5I-