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Find the equation of the line passing through the points (-1, 4) and (3, 2).
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How do you write the standard form of the equation of the line passing through the points M(-4,-2) and N(4,7)?
How do you find
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standard form is y=mx+b where m is slope, x is x value in (x,y) and b is the y intercept. Find slope
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How do you write the standard form of the equation of the line passing through the points M(-4,-2) and N(4,7)?
How do you find
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for the first: slope = (7+2)/(4+4) = 9/8 then using the point (4,7) y-7 = (9/8)(x-4) 8y - 56 = 9x -
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Determine the equation of the line described by the given information.
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a) We use the slope-point formula y-y1 = m (x - x1) y - 6 = -2/3(x - 0) y - 6 = -2/3x + 0 y = -2/3x
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Which function has the greatest rate of change?
Responses A y = 3x - 4y = 3x - 4 B 4y - 8x = 14y - 8x = 1 C a line passing
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Find the equation of the line passing through the points: (-5,-5) and (6,-5)
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To find the equation of a line passing through two points, you need to find the slope and the
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find the equation of the straight line through A(3,20) which is perpendicular to the line passing through the points B(-2,8) and
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slope of BC = (8-8)/(11=2) = 0 so BC is a horizontal line Thus the line through A must be a vertical
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Find an equation of the line passing through the point (−1, 3) and parallel to the line joining the points (−3, 4) and (4,
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find the slope between the points (−3, 4) and (4, −1), call it m then using the other point: y-3
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Find an equation of the line passing through the point (−1, 9) and parallel to the line joining the points (−3, 4) and
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the line through (−3, 4) and (4, −1) has slope -5/7 Any line oarallel to it has the same slope.
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A line passing through the points (1, 4) (-3, t)
has a slope equal to 3. Find the value of t Enter each line of work as an
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First, let's calculate the slope using the formula: m = (y2 - y1) / (x2 - x1) Given points: (1, 4)
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What is the equation of the line passing through (4, 2) and perpendicular to the line passing through the points (9,7) and
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since the line is perpendicular, their slopes are negative reciprocals of each other, that means,
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