500ml of 0.1M CaCl2 is required for protimes. How many grams of CaCl2 * H2O should you weight out?
You need 0.500 x 0.1 = 0.05 moles CaCl2 or
0.05 moles x molar mass CaCl2 = ?? grams CaCl2.
Convert ?? g CaCl2 to CaCl2.H2O.
How do i convert g CaCl2 to g CaCl2*H2O?
To calculate the mass of CaCl2 * H2O required, we need to determine the molar mass of CaCl2 * H2O and then use the given concentration and volume information.
1. Determine the molar mass of CaCl2 * H2O:
- The molar mass of Ca is 40.08 g/mol.
- The molar mass of Cl is 35.45 g/mol.
- The molar mass of H2O is (2 × 1.01 g/mol) + 16.00 g/mol = 18.02 g/mol.
- So, the molar mass of CaCl2 * H2O is (40.08 g/mol) + (2 × 35.45 g/mol) + 18.02 g/mol = 147.01 g/mol.
2. Calculate the number of moles of CaCl2 using the given concentration and volume:
- Concentration (C) = 0.1 mol/L.
- Volume (V) = 500 mL = 0.5 L (since 1 L = 1000 mL).
- Number of moles (n) = C × V = 0.1 mol/L × 0.5 L = 0.05 mol.
3. Calculate the mass of CaCl2 * H2O:
- Mass = Number of moles × Molar mass = 0.05 mol × 147.01 g/mol = 7.35 g (rounded to two decimal places).
Therefore, you should weigh out approximately 7.35 grams of CaCl2 * H2O for the desired quantity of 500 mL of 0.1 M CaCl2 solution for protimes.