Please help- A small fish is dropped by a pelican that is rising steadily at 0.50 m/s. How far below the pelican is the fish after 2.5 s?

Answers.
61m
29.3
30.6
1.1m

I just started school and I'm totally lost-If someone could explain formula to me I'd really appreaciate it
Thank you

D = d1 + d2

D= 0.5m/s * 2.50s + (9.8/2)m/s^2 *(2.5s)^2
D = 1.25 + 30.6 = 31.9 METERS.

Their distance(30.6) doesn't seem to include the distance the pelican traveled (1.25m) after dropping the fish.

Of course! I'd be happy to explain the formula to you.

To solve this problem, we can use the formula for distance traveled (d) given initial velocity (u), time (t), and acceleration (a):

d = ut + (1/2)at^2

In this case, we can assume the initial velocity of the fish is 0 m/s (since it was dropped), the acceleration due to gravity (a) is approximately 9.8 m/s^2 (assuming we are on Earth), and the time (t) is given as 2.5 seconds.

Plugging in the values into the formula, we get:

d = 0 * 2.5 + (1/2) * 9.8 * (2.5)^2

Simplifying the equation:

d = 0 + (1/2) * 9.8 * 6.25

d = 0 + 4.9 * 6.25

d = 30.625

Therefore, the fish is approximately 30.6 meters below the pelican after 2.5 seconds.

I hope that helps! Let me know if you have any other questions.

Of course, I'd be happy to help explain the formula and how to solve this problem step by step!

In this problem, we are given the velocity of the pelican (0.50 m/s) and the time (2.5 s). We need to find the distance below the pelican where the fish ends up.

The formula we can use to solve this problem is the distance formula:

distance = initial velocity x time + (0.5 x acceleration x time^2)

There are a few important things to note about this formula:

- Initial velocity: The initial velocity in this case is the velocity at which the fish is dropped, which is zero. This is because the fish starts from rest.

- Time: The given time in the problem is 2.5 seconds.

- Acceleration: Here, we assume that the pelican is rising steadily, which means there is no change in velocity over time. Therefore, the acceleration is zero.

Let's plug in the values into the formula:

distance = 0 x 2.5 + (0.5 x 0 x 2.5^2)
distance = 0 + 0
distance = 0

Based on the calculation, the distance below the pelican where the fish ends up after 2.5 seconds is 0 meters. However, none of the answer options provided match this result.

Please double-check the given answers or provide any additional information you may have, so we can further assist you!